# Ex 4.2 – Quadratic Equation (Full Exercise Solution + Video) MATHS – NCERT | Class 10

By | 27th December 2018

SUBJECT – MATHS
CLASS – X (10th)
QUESTION FROM – Quadratic Equation (Exercise 4.2)
ALL EXTRA & IMPORTANT QUESTION ANSWER FOR 2019 EXAMS

##### Ex 4.2 – Quadratic Equation (Full Exercise Solution + Video) MATHS – NCERT | Class 10

###### Q1. Find the roots of the following quadratic equations by factorisation:

(i) x2 -3x – 10 = 0
(ii) 2x2 + x – 6 = 0
(iii) √2x2 + 7x + 5√2 = 0
(iv) 2x2 – x + $\frac { 1 }{ 8 }$ = 0 8
(v) 100 x2 – 20 X + 1 = 0

Ex 4.2 Quadratic Equation (Q.1) Class 10 Maths NCERT Solution In Hindi

###### Question 2 :: Solve the following situations mathematically:

(i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.

(ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was ₹750. We would like to find out the number of toys produced on that day.

Question 3 :: Find two numbers whose sum is 27 and product is 182.

Ex 4.2 Quadratic Equation (Q.3) class 10 Maths NCERT Solution In Hindi

###### Question 5 :: The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.

Question 6 :: A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was ₹90, find the number of articles produced and the cost of each article.

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